## Why is pow() function giving wrong answer

I'm trying to multiply 2, 3 digit numbers. I used 2 for loops (nested) and multiplied each digit of num1 with num2, and shifted each result to the appropriate place using pow(). So the problem is pow(10,3) is coming out to be 299 instead of 300.

I haven't tried much as but used printf to find what is actually happening in the runtime and this is what I have found. the values of tempR after shift should be

`5,40,300,100,800,6000,1500,12000,90000`

but are coming as

`5,40,299,100,799,6000,1500,12000,89999`

```
int main(void)
{
int result; // final result
int tempR; // temporary for each iteration
char a[] = "345"; // number 1
char b[] = "321"; // number 2
for(int i = 2;i>= 0 ; i --)
{
for(int j = 2;j >= 0 ; j --)
{
int shift = abs(i-2 + j -2);
printf("%d
",shift); //used to see the values of shift.
//and it is coming as expected
tempR = (int)(b[i] - '0') * (int)(a[j] - '0');
printf("%d
",tempR); // value to tempR is perfect
tempR = tempR*pow(10,shift);
printf("%d
",tempR); // here the problem starts
result += tempR;
}
}
printf("%d",result);
}
```